Considerando un C.V. = 0.50 de la variable consumo específico de leña en el sector residencial y nivel de confianza = 0.95. e = error probable.
no=
(cv2. t2
,
)/ e2
n = no/(1 + no/N)
|
Universo |
Muestra |
|||
|
|
e=10% |
e=15% |
e=20% |
e=30% |
|
40 |
28 |
21 |
15 |
9 |
|
50 |
33 |
23 |
16 |
9 |
|
60 |
37 |
25 |
17 |
9 |
|
100 |
50 |
30 |
20 |
10 |
|
150 |
59 |
34 |
21 |
10 |
|
200 |
66 |
36 |
22 |
10 |
|
250 |
71 |
37 |
22 |
10 |
|
300 |
74 |
38 |
23 |
11 |
|
350 |
77 |
39 |
23 |
11 |
|
400 |
79 |
39 |
23 |
11 |
|
500 |
82 |
40 |
23 |
11 |
|
600 |
85 |
41 |
24 |
11 |
|
700 |
86 |
41 |
24 |
11 |
|
800 |
88 |
42 |
24 |
11 |
|
900 |
89 |
42 |
24 |
11 |
|
1000 |
90 |
42 |
24 |
11 |
|
2500 |
95 |
43 |
24 |
11 |
|
5000 |
97 |
43 |
25 |
11 |